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Re: Math help

Posted by monkeyLostInHead on 2024-August-9 15:54:42, Friday
In reply to Math help posted by Pharmakon on 2024-August-9 14:12:01, Friday




the logit of a probability is defined as

L = ln(p/(1-p)

p in this case is the value we want to reach ( ie 56%)

Probabilities range from 0 to 1, whereas logits range from minus infinity to plus infinity

A probability of 0.5 corresponds to a logit of 0
A probability of 0.55 corresponds to a logit of 0.2

so in order to reach the probability of 0.56 quoted in the text, we would need to have a logit(probability) of around 0.2, and not -41.78

plug 0.56 into the formula above ( L = ln(p/(1-p))
we get ln(0.56/0.44) = 0.24

so in order to get a probability of 0.56, the logit ( right hand side of the equation) would need to be 0.24.

So maybe its not a straightforward logit function?




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